the 142857

（transverse looking）of the“I have a stick ,I take it half (or cut it half) every day ,I can't finish it forever and forever”. 

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Round shape（or universal joint）looking of the“I have a stick ,I take it half (or cut it half) every day ,I can't finish it forever and forever”

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Now I take 50 point to do 4 layers .The first layer is the center’s too extreme. The second layer is the future too extreme（any one of the 7 points）

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The first layer is the center’s too extreme.

          It keep “bear”:
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Anyone could be the center’s too extreme relatively.

I randomly fine one and give it an English name that hector.

If I set the hector is the center too extreme as an new “one”

The new comer that hector would “bear” ：

Again，I randomly fine one and give it an English name that Achilles .

The new comer that Achilles would “bear”：

When :
1÷7=0.142857
0.142857 × 1 = 0.142857
0.142857 × 2 = 0.285714
0.142857 × 3 =0.428571
0.142857 × 4 = 0.571428
0.142857 × 5 =0.714285
0.142857 × 6 = 0.857142
0.142857 × 7 = 0.999999=1

The 142857 would keep cycle.

The following I take from “Wikipedia”

http://en.wikipedia.org/wiki/142857_(number)

1 × 142,857 = 142,857

2 × 142,857 = 285,714

3 × 142,857 = 428,571

4 × 142,857 = 571,428

5 × 142,857 = 714,285

6 × 142,857 = 857,142

7 × 142,857 = 999,999

If you multiply by an integer greater than 7, there is a simple process to get to a cyclic permutation of 142857. By adding the first six digits (ones through hundred thousands) to the remaining digits and repeating this process until you have only the six digits left, it will result in a cyclic permutation of 142857

142857 × 8 = 1142856

1 + 142856 = 142857

142857 × 815 = 116428455

116 + 428455 = 428571

142857² = 142857 × 142857 = 20408122449

20408 + 122449 = 142857

Multiplying by a multiple of 7 will result in 999999 through this process

142857 × 7⁴ = 342999657

342 + 999657 = 999999

If you square the last three digits and subtract the square of the first three digits, you also get back a cyclic permutation of the number.

857² = 734449

142² = 20164

734449 − 20164 = 714285

It is the repeating part in the decimal expansion of the rational number 1/7 = 0.142857. Thus, multiples of 1/7 are simply repeated copies of the corresponding multiples of 142857:

1 ÷ 7 = 0.142857

2 ÷ 7 = 0.285714

3 ÷ 7 = 0.428571

4 ÷ 7 = 0.571428

5 ÷ 7 = 0.714285

6 ÷ 7 = 0.857142

7 ÷ 7 = 0.999999

8 ÷ 7 = 1.142857

9 ÷ 7 = 1.285714

The figure could explain the 142857 

If I only “recognize” the points:

在前面的章节中，我们也可以从奇偶数在加减法和乘除法中不同的对冲数序观察到七这个数的特别之处。

从3×9=27 ，4×8=32中去发现七的这个特别之处很明显：

如下是放大图：

如上这些案例表明，7在某种情况下，七可以是奇数的开始。但偶数的情况就不同了，偶数依然是由二开始。为什么会有这样现象？

当七开平方时，是大衍之数，也就是七自己乘以自己的时候得到了49，7×7=49。这个九也是意味着七自乘的时候达到了数的尽头。

假设这世上只有一二三四五六，并假设这世上还没有出现七八九。也就是说假如我设六进制，那么在此六进制中，但凡对冲两数的和为七，在这个六进制中，因为3+4=7三和四是对冲数，2+5=7二和五是对冲数，1+6=7一和六是对冲数。

以上观察发现，七可以是管理六进制的一个奇数，也就是说七在运行时包囊了一二三四五六，同时一和六是太阴数：

所以七会有这种特别现象，七也是唯一的一个数字和气功的气是同音字。数必至七而复，气必至七而更。我不是学中医的，不过好像中医学对7年作为生命中的每一个节点也是有说法的。